Introduction to Chemical Engineering Processes/Multiple …
On the crusher: There are 3 unknowns (m1, m2, and xS2). We can write 2 independent mass balances. Thus the crusher has 3-2 = 1 DOF; Therefore for the system as a whole: Sum of DOF for unit operations = 2 + 1 = 3 DOF; Number of intermediate variables = 2 (m2 and xS2) Total DOF = 3 - 2 = 1 DOF. Hence the problem is …
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